In the figure, ABC is a triangle in which AB = AC. X and Y are points on AB and AC such that AX =AY. Then $Δ A B Y ≅ Δ A C X$

True

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False

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Solution

The correct option is A True
$T h e s t a t e m e n t i s t r u e$
$C o n s i d e r △ A B Y a n d △ A C X$
$A B = A C (g i v e n)$
$A X = A Y (g i v e n)$
$∠ A = ∠ A (c o m m o n)$
$∴ △ A B Y ≅ △ A C X {B y S A S c o n g r u e n c y}$

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In the figure, ABC is a triangle in which AB = AC. X and Y are points on AB and AC such that AX =AY. Then ΔABY≅ΔACX

The correct option is A TrueThestatementistrueConsider△ABYand△ACXAB=AC(given)AX=AY(given)∠A=∠A(common)∴△ABY≅△ACX{BySAScongruency}

In the figure, ABC is a triangle in which AB = AC. X and Y are points on AB and AC such that AX =AY. Then $Δ A B Y ≅ Δ A C X$

The correct option is A True
$T h e s t a t e m e n t i s t r u e$
$C o n s i d e r △ A B Y a n d △ A C X$
$A B = A C (g i v e n)$
$A X = A Y (g i v e n)$
$∠ A = ∠ A (c o m m o n)$
$∴ △ A B Y ≅ △ A C X {B y S A S c o n g r u e n c y}$