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Construction of Triangles: When 2 Sides and Included Angle Are Given

In the figure...

Question

In the figure, ABC is a triangle in which AD bisects $∠ A, A C = B C, ∠ B = 72^{o}$ and CD =1 cm. Length of BD (in cm) is:

1

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\frac{1}{2}

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\frac{\sqrt{5} - 1}{2}

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\frac{\sqrt{3} + 1}{2}

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Solution

The correct option is C $\frac{\sqrt{5} - 1}{2}$

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Similar questions

Q. In the figure,

A B C

is a triangle in which

A D

bisects

∠ A

A C =

B C

∠ B = 72^{\circ}

and

C D = 1 c m

. Length of

A B (i n c m)

In the figure given below AB = 3 cm, AC = 5 cm and AD = 4 cm and D is the midpoint of BC. Then the length of BD is :

Q. In

△ A B C

C

is a point on

B D

such that

B C : C D = 1 : 2

and

△ A B C

is an equilateral triangle. Prove that

{A D}^{2} = 7 {A C}^{2}

$△$ ABC is a right angled triangle, right angled at B. BD is a perpendicular to AC as shown in the figure. If AD:DC = 1:2, then $\frac{{A B}^{2}}{{B C}^{2}}$ is ____.

A B C

is a triangle in which

∠ B = 2 ∠ C

D

is point on the side

B C

such that

A D

bisects

∠ B A C

and

A B = C D

. Prove that

∠ B A C = 72^{o}

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In the figure, ABC is a triangle in which AD bisects ∠A,AC=BC,∠B=72o and CD =1 cm. Length of BD (in cm) is:

The correct option is C √5−12

In the figure, ABC is a triangle in which AD bisects $∠ A, A C = B C, ∠ B = 72^{o}$ and CD =1 cm. Length of BD (in cm) is:

The correct option is C $\frac{\sqrt{5} - 1}{2}$