In the figure , ABCD is a parallelogram. If AB = 12 cm, AE = 7.5 cm, CF = 15 cm, then AD =

3 cm

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6 cm

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8 cm

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10.5 cm

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Solution

The correct option is B
6 cm

IN ||gm ABCD, AB = 12 cm
AE = 7.5 cm
$∴ A r e a o f | | g m A B C D = b a s e \times h e i g h t$
$= A B \times A E = 12 \times 7.5 c m^{2} = 90 c m^{2}$

$N o w, a r e a | | g m A B C D = 90 c m^{2}$
And altitude CF = 15 cm
$∴ B a s e A D = \frac{A r e a}{A l t i t u d e} = \frac{90}{15} = 6 c m$

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