In the figure, ABCD is a parallelogram in which ∠ADC=105∘,∠CBE is
ABCD is a parallelogram Therefore, ∠ADC=∠ABC=105∘[ Opposite angles are equal] ∠ABC+∠CBE=180∘ [Linear pair] ∠CBE=180∘−105∘=75∘ Hence, ∠CBE=75∘.
In the figure, AB is parallel to DC and AD is parallel to BC,
If ∠ADC=105∘, ∠CBE=? is
In the figure, ABCD is a quadrilateral in which \(\angle ADC=105^\circ ~and~ \angle ADC=~\angle ABC. Find \angle CBE\).