1
Question
In the figure, ABCD is a parallelogram in which ∠ADC=105∘. Find the value of ∠CBE.
[2 Marks]
[2 Marks]
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Solution
ABCD is a parallelogram.
Therefore, ∠ADC=∠ABC=105∘ [Opposite angles of a parallelogram are equal] [1 Mark]
Now ∠ABC+∠CBE=180∘ [Linear pair]
∠CBE=180∘−105∘=75∘
Hence, ∠CBE=75∘. [1 Mark]
Therefore, ∠ADC=∠ABC=105∘ [Opposite angles of a parallelogram are equal] [1 Mark]
Now ∠ABC+∠CBE=180∘ [Linear pair]
∠CBE=180∘−105∘=75∘
Hence, ∠CBE=75∘. [1 Mark]
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