In the figure- ABCD is a parallelogram in which - ADC - 105- The value of - CBE is

ABCD is a parallelogram ∴, ∠ ADC = nbsp;∠ ABC = 105^∘[Opposite angles of a parallelogram are equal] ∠ nbsp;ABC + nbsp;∠ CBE = 180^∘ [Linear pair] nbsp; ...

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Byju's Answer

Standard VIII

Mathematics

Sum of Angles of a Quadrilateral

In the figure...

Question

In the figure, ABCD is a parallelogram in which $∠ A D C = 105^{\circ}$ . The value of $∠ C B E$ is

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Solution

ABCD is a parallelogram
$∴, ∠ A D C = ∠ A B C = 105^{\circ}$ [Opposite angles of a parallelogram are equal]
$∠ A B C + ∠ C B E = 180^{\circ}$ [Linear pair]
$∠ C B E = 180^{\circ} - 105^{\circ} = 75^{\circ}$
Hence, $∠ C B E = 75^{\circ}$

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In the figure, ABCD is a parallelogram in which ∠ADC=105∘. The value of ∠CBE is

ABCD is a parallelogram ∴,∠ADC=∠ABC=105∘[Opposite angles of a parallelogram are equal] ∠ABC+∠CBE=180∘ [Linear pair] ∠CBE=180∘−105∘=75∘ Hence, ∠CBE=75∘

In the figure, ABCD is a parallelogram in which $∠ A D C = 105^{\circ}$ . The value of $∠ C B E$ is

ABCD is a parallelogram
$∴, ∠ A D C = ∠ A B C = 105^{\circ}$ [Opposite angles of a parallelogram are equal]
$∠ A B C + ∠ C B E = 180^{\circ}$ [Linear pair]
$∠ C B E = 180^{\circ} - 105^{\circ} = 75^{\circ}$
Hence, $∠ C B E = 75^{\circ}$