In the figure, ABCD is a parallelogram in which ∠DCB=60∘,∠CBE is
ABCD is a parallelogram.
So, AE ∥ CD.
⇒∠DCB=∠CBE (Alternate interior angles)
Hence, ∠CBE=60∘
In the figure, ABCD is a parallelogram in which ∠ADC=105∘,∠CBE is
In the figure, AB is parallel to DC and AD is parallel to BC,
If ∠ADC=105∘, ∠CBE=? is
In the figure, ABCD is a quadrilateral in which \(\angle ADC=105^\circ ~and~ \angle ADC=~\angle ABC. Find \angle CBE\).
In the given figure, ABCD is parallelogram.If ∠A=75∘, then ∠B is