Question

In the figure, $ABCD$ is a parallelogram, $P$ is a point on $AB$ produced and $DN\perp AB$.

If $AB=8cm$ and $DN=3cm$. Find the area of $△CPD$.

Answer 1

$Area\left(△CPD\right)=Area\left(△CDA\right)$ [Triangle formed between same pair of parallel lines and with the same base have equal areas]

$=\frac{1}{2}\times \left(AreaABCD\right)$ [Since diagonal parallelograam divide it in two equal areas]

$=\frac{1}{2}\times AB\times DN$

$=\frac{1}{2}\times 8\times 3$

$=12c{m}^2$