In the figure, ABCD is a parallelogram. Sides AB and BC are equal to 15 cm and 6 cm, respectively. If DF = 4 cm, what is the value of BE?

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Solution

Given
BC = 6 cm
AD = BC (Parallel sides of a parallelogram are equal)
Area (ABCD) = Base × Height
= AB × DF = AD × BE

AB × DF = 15 cm × 4 cm
= 60 sq. cm
AD × BE = 60 sq. cm
$\Rightarrow$ BE × 6 cm = 60 sq. cm
$\Rightarrow$ BE = 10 cm

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In the figure, ABCD is a parallelogram. Sides AB and BC are equal to 15 cm and 6 cm, respectively. If DF = 4 cm, what is the value of BE?

Given BC = 6 cm AD = BC (Parallel sides of a parallelogram are equal) Area (ABCD) = Base × Height = AB × DF = AD × BE AB × DF = 15 cm × 4 cm = 60 sq. cm AD × BE = 60 sq. cm ⇒BE × 6 cm = 60 sq. cm ⇒BE = 10 cm

Given
BC = 6 cm
AD = BC (Parallel sides of a parallelogram are equal)
Area (ABCD) = Base × Height
= AB × DF = AD × BE

AB × DF = 15 cm × 4 cm
= 60 sq. cm
AD × BE = 60 sq. cm
$\Rightarrow$ BE × 6 cm = 60 sq. cm
$\Rightarrow$ BE = 10 cm