In the figure ABCD is a square. A line segment DX cuts the side BC at X and the diagonal AC at O such that ∠COD = 105o and ∠OXC = y. Then y is equal to
60o
∠OCX = 45o (diagonal bisects the angle of a square)
∠COD + ∠COX = 180o (linear pair)
∠COX = 75o, In COX, by angle sum property ∠OXC = 60o
Hence y = 60o