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Question
In the figure, ABCD is a trapezium in which AB || DC and its diagonals AC and BD intersect at O. Then ar(∆AOD) is equal to
In the figure, ABCD is a trapezium in which AB || DC and its diagonals AC and BD intersect at O. Then ar(∆AOD) is equal to
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Solution
The correct option is D ar(∆BOC)
ar(∆CDA) = ar(∆CDB) (triangles on the same base and between same parallels)
=> ar(∆CDA) - ar(∆OCD) = ar(∆CDB) - ar(∆OCD)
=> ar(∆AOD) = ar(∆BOC)
ar(∆BOC)
ar(∆CDA) = ar(∆CDB) (triangles on the same base and between same parallels)
=> ar(∆CDA) - ar(∆OCD) = ar(∆CDB) - ar(∆OCD)
=> ar(∆AOD) = ar(∆BOC)
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