In the figure above, straight lines AB and CD intersect at P, and AC||BD. ThenΔAPC and ΔBPD are similar.If true enter 1 else 0.
Open in App
Solution
In △APC and △BPD ∠APC=∠BPD (Vertically opposite angles) ∠PAC=∠PBD (Alternate angles of parallel lines AC and BD) ∠PCA=∠PDB (Third angle) Thus, △APC∼△BPD (AAA rule)