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Right Angle

In the figure...

Question

In the figure above, triangle ABC is equilateral, and point P is equidistant from vertices A, B, and C. If triangle ABC is rotated clockwise about point P, what is the minimum number of degrees the triangle must be rotated so that point B will be in the position where point A is now?

60

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120

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180

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240

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270

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Solution

The correct option is D $240$
Each of the three central angles is $= \frac{360^{0}}{3} = 120^{0}$
Thus, in order point B to be in the position where point A is, B should rotate clockwise = $120^{0} + 120^{0} = 240^{0}$

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In the figure above, triangle ABC is equilateral, and point P is equidistant from vertices A, B, and C. If triangle ABC is rotated clockwise about point P, what is the minimum number of degrees the triangle must be rotated so that point B will be in the position where point A is now?

The correct option is D 240Each of the three central angles is =36003=1200Thus, in order point B to be in the position where point A is, B should rotate clockwise = 1200+1200=2400

The correct option is D $240$
Each of the three central angles is $= \frac{360^{0}}{3} = 120^{0}$
Thus, in order point B to be in the position where point A is, B should rotate clockwise = $120^{0} + 120^{0} = 240^{0}$