In the figure, AC=10 cm, PC=15 cm, AB=8 cm, find PB.
6 cm
7 cm
8 cm
9 cm
In ΔABC, AB2+BC2=AC2⇒102=82+BC2 ⇒BC=6 cm PB=PC−BC=15−6=9 cm Hence, PB=9 cm.
In the figure, AC=10cm, PC= 15cm, PQ=12cm, find PB?
In the given figure, AB = AC, AD = AE = 5 cm and DC = 8 cm. Length of EB is.
Question: In the figure, AC = 10cm, PC = 15cm, PQ = 12 cm, find PB