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Question

In the figure, AC is tangent to the circle at O and CB is is the perpendicular from C to O. If the radius of the circle is r, then, select the statement that is true.


A

r2=OB×OA

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B

8r2=OB×OA

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C

7r2=OB×OA

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D

r3=OB×OA

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Solution

The correct option is A

r2=OB×OA


[Radius is perpendicular to the tangent at point of contact]

Join OC

OC = r

OC ⟂ AC

In △OCA and △OBC,

OCA=OBC=90° [as each of them are 90°]

OCA=OBC [Common angle]

△OCA ~ △OBC [AA similarity]

OCOB=OAOC

= OC2=OB×OA

r2=OB×OA


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