In the figure- AD -12 cm - AB -20 cm and AE -10 cm - Find EC -A- 14 cmB- 8 cmC- 15 cmD- 10 cm

The correct option is A 14 cmΔ ADE Δ ACB (A A A Property) ∴ AE/AB = AD/AC 10/20 = 12/AC⇒ AC = 24 cm EC = AC AE = 24 10 = 14 cm ...

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In the figure...

Question

In the figure, AD = 12 cm, AB = 20 cm and AE = 10 cm. Find EC:

14 cm

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10 cm

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8 cm

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15 cm

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Solution

The correct option is A 14 cm
$Δ A D E$ ~ $Δ A C B$ (A - A - A Property)
$∴$ $\frac{A E}{A B}$ = $\frac{A D}{A C}$
$\frac{10}{20} = \frac{12}{A C} \Rightarrow A C = 24 c m$
$E C = A C - A E = 24 - 10 = 14 c m$

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In the above figure ∆ABC~∆ADE. Given that AD=x cm, DB =x-3 cm, AE=4cm, EC=3 cm. What is the value of x?

Q. In figure,

A B C D

is a parallelogram,

A E ⊥ D C

and

C F ⊥ A D

. If

A B = 16 c m, A E = 8 c m

and

C F = 10 c m

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A D

D and E are points on the sides AB and AC respectively of a $Δ A B C$ . In each of the follwing cases, determine whether DE || BC or not.

(i) AD = 5.7 cm, DB = 9.5 cm, AE = 4.8 cm and EC = 8 cm.

(ii) AB = 11.7 cm, AC = 11.2 cm, BD = 6.5 cm and AE = 4.2 cm.

(iii) AB = 10.8 cm, AD = 6.3 cm, AC = 9.6 cm and EC = 4 cm.

(iv) AD = 7.2 cm, AE = 6.4 cm, AB = 12 cm and AC = 10 cm.

In the given Figure,

A B C D

is a parallelogram,

A E ⊥ D C

and

C F ⊥ A D

. If

A B = 16 c m, A E = 8 c m

and

C F = 10 c m

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Q. D and E are points on the sides AB and AC respectively of a

∆ A B C

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or not.

(i)

A D = 5.7 cm, D B = 9.5 cm, B D = 4.8 cm and E C = 8 cm .

(ii)

A B = 11.7 cm, A C = 11.2 cm, B D = 6.5 cm and A E = 4.2 cm .

(iii)

A B = 10.8 cm, A D = 6.3 cm, A C = 9.6 cm and E C = 4 cm .

(iv)

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In the figure, AD = 12 cm, AB = 20 cm and AE = 10 cm. Find EC:

The correct option is A 14 cmΔADE~ΔACB (A - A - A Property) ∴ AEAB = ADAC 1020=12AC⇒AC=24cm EC=AC−AE=24−10=14 cm

The correct option is A 14 cm
$Δ A D E$ ~ $Δ A C B$ (A - A - A Property)
$∴$ $\frac{A E}{A B}$ = $\frac{A D}{A C}$
$\frac{10}{20} = \frac{12}{A C} \Rightarrow A C = 24 c m$
$E C = A C - A E = 24 - 10 = 14 c m$