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Question

In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that: ΔPDC~ΔBEC


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Solution

To prove that PDC~BEC

Given that altitudes AD and CE ofABC intersect each other at the point P

Consider PDC and BEC

CEB=CDP (Each angle equal to 90°)

BCE=PCD (Common angle)

By AA similarity criteria PDC~BEC

Hence, it is proved that PDC~BEC.


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