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Question

In the figure, an idea liquid flow through the tube, this is of uniform cross section. The liquid has velocities vA and vB, and pressures PA and PB at the point A and point B, respectively. Then
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A
vA = vB
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B
vA > vB
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C
PA > PB
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D
PB > PA
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Solution

The correct options are
A vA = vB
D PB > PA
Applying Bernoulli's equation keeping pressure energy and potential energy constant, we get,
12ρV2A=12ρV2BVA=VB
However, with the height difference between points A and B causes a difference in pressure PA&PB where PA=ρghA and PB=ρghB and since hB>hA>Pb>PA
where h= depth of point.


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