You visited us 1 times! Enjoying our articles? Unlock Full Access!

Angle Subtended by an Arc of a Circle at the Centre

In the figure...

Question

In the figure, $∠$ ACB $= 42^{o}$ , find $^x$ .

Open in App

Solution

Given that:
$∠ A C B = 42^{\circ}$
$x = 2 ∠ A C B = 2 \times 42^{\circ} = 84^{\circ}$ (Angle subtended by an arc at the centre is twice of angle subtended by it at any point on the circle.)

Suggest Corrections

Similar questions

θ = 42^{o}

x

∠

A P O

= 42^{o}

∠

C Q O

= 38^{o}

∠

P O Q

∠

= 26^{o}

∠

= 36^{o}

^x

^y

∠ A C B = 40^{o}

∠ O A B

∠ A C B

Join BYJU'S Learning Program