Question

In the figure $\angle ADC={130}^o$ and chord BC = chord BE. Find $\angle CBO$.

• A. ${40}^o$
• B. ${50}^o$
• C. ${60}^o$
• D. ${100}^o$

Answer 1

The correct option is B ${50}^o$

$ABCD$ is a cyclic quadrilateral.

Also, $\angle ADC={130}^o$.

We know, opposite angles of a cyclic quadrilateral are supplementary.

Then, $\angle ADC+\angle CBA={180}^o$

$\angle CBO=\angle CBA={180}^o-{30}^o={50}^{\circ }$.

Therefore, option $B$ is correct.