In the figure, ∠AOC and ∠BOC form a linear pair. If a−2b=30∘, find a and b.
Given: ∠AOC and ∠BOC form a linear pair
Therefore,
∠AOC+∠BOC=180∘
⇒a+b=180∘ [As ∠AOC=a and ∠BOC=b]
⇒a=180∘−b...(i)
Putting the value from (i) in a−2b=30∘, we get,
⇒180∘−b−2b=30∘
⇒−3b=−150∘
⇒b=150∘3∘=50∘
Therefore,
a=180∘−50∘=130∘
Hence,∠AOC=130∘ and ∠BOC=50∘