In the figure : $∠ P S Q = 90^{o}, P Q = 10 c m, Q S = 6 c m$ and $R Q = 9 c m$ . Calculate the length of $P R$ .

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Solution

According to question,

$△ P S R$ and $△ P S Q$ are similar triangles,

So, ratio of their corresponding sides are equal,

i.e; $\frac{P R}{P Q} = \frac{S R}{Q R}$

$⟹ \frac{P R}{10} = \frac{9 + 6}{6}$

$⟹ P R = 25 c m$

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∠ P S Q = 90^{\circ}, P Q = 10 c m, Q S = 6 c m

R Q = 9 c m

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P R

In the figure: $∠ P S Q = 90^{\circ},$
PQ = 10 cm, QS = 6 cm and RQ = 9 cm.
Calculate the length of PR.

∠ P S R = 90^{o}

= 10

Q S = 6

= 9

In the figure: $∠ P S Q = 90^{\circ},$
PQ = 10 cm, QS = 6 cm and RQ = 9 cm.
Calculate the length of PR.

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