Question

In the figure, AOB is a straight line. The measure of $\Delta COD$ is equal to

• A. ${60}^0$
• B. ${50}^0$
• C. ${100}^0$
• D. ${20}^0$

Answer 1

Answer: (C)

${100}^0$

$AOB$ is a straight line

$\therefore x+{20}^{\circ }+2x-{20}^{\circ }+{60}^{\circ }={180}^{\circ }$

$\Rightarrow 3x={180}^{\circ }-{60}^{\circ }$

$\Rightarrow x={40}^{\circ }$

$\angle COD=2x+{20}^{\circ }$

$\angle COD=(2\times {40}^{\circ })+{20}^{\circ }={100}^{\circ }$