Question

In the figure, AP and AQ are tangents to the circle with centre O, from an external point A. If ∠PAQ = 70^o then APQ is equal to:

• A. 35^o
• B. 110^o
• C. 55^o
• D. 125^o

Answer 1

The correct option is C

55^o

We know that tangents from an external point to the circle are equal.

So, AP = AQ

=>∠AQP = ∠APQ

In APQ,

∠APQ + ∠AQP + ∠PAQ = 180^o

2∠APQ = 180^o - 70^o (∠PAQ = 70^o)

2∠APQ = 110^o

∠APQ = 55^o