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Question

In the figure as shown two blocks are connected by a string over a pulley.

Calculate the total work done by tension force on the system for 1 m distance covered.

A
803 N
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B
803 N
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C
Zero
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D
None
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Solution

The correct option is C Zero
Drawing FBD of the system.


Applying 2nd law, on both the blocks

T2g=2aT20=2a ...(i)
40T=4a ...(ii)

We get tention (T)
T=803 N
Work done by T for 4 kg=F.d

W4kg=803N. Here the work done is negative as T and displacement are in opposite direction d

Work done by T for 2 kg = 803 N
Total work done by the tension is = 803+803=0
Hence option C is the correct answer

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