In the figure as shown two blocks are connected by a string over a pulley.
Calculate the total work done by tension force on the system for 1m distance covered.
A
803N
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B
−803N
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C
Zero
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D
None
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Solution
The correct option is C Zero Drawing FBD of the system.
∴ Applying 2nd law, on both the blocks
T−2g=2a⇒T−20=2a...(i) 40−T=4a...(ii)
We get tention (T) ⇒T=803N
Work done by T for 4kg=→F.→d
W4kg=−803N. Here the work done is negative as T and displacement are in opposite direction →d
Work done by T for 2kg = 803N ∴ Total work done by the tension is = −803+803=0
Hence option C is the correct answer