Question

In the figure AT and BT are the tangents to a circle with centre O. Another tangent PQ is drawn such that TP = TQ. Show that ΔTAB ||| ΔTPQ.

Answer 1

The given figure is:

We know that the lengths of tangents to a circle from an external point are equal.

∴AT = BT and TP = TQ

∴and

In ΔTAB and ΔTPQ, and

Hence, ΔTAB ||| ΔTPQ