In the figure below, if ∠PQR = ∠PRQ, then, which of the following is/are true?
∠PQR = ∠PQS
∠PRQ = ∠PRT
∠PQS = ∠PRT
∠QPR = 90∘
∠PQS + ∠PQR = ∠PRQ + ∠PRT (by linear pair)
But, it is given that, ∠PQR = ∠PRQ
Therefore, ∠PQS = ∠PRT
In below shown figure, PSSQ= PTTR and∠PST= ∠PRQ. Then ΔPQR is an isosceles Triangle.
In the figure shown below, PSSQ=PTTR and ∠PST=∠PRQ. Then △PQR is __ triangle.