Question

In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(\angle POQ+\angle QOR+\angle SOR+\angle POS)}{3}$.

• A. ${60}^{\circ }$
• B. ${120}^{\circ }$
• C. ${90}^{\circ }$
• D. ${30}^{\circ }$

Answer 1

The correct option is B ${120}^{\circ }$

The rays OP, OQ, OR and OS originate from O. Angle about the point O is ${360}^o$.

$\Rightarrow \angle$POQ + $\angle$QOR + $\angle$SOR + $\angle$POS = ${360}^{\circ }$

$\therefore \frac{(\angle POQ+\angle QOR+\angle SOR+\angle POS)}{3}$ = $\frac{{360}^{\circ }}{3}$ = ${120}^{\circ }$