In the figure below- x - 30- The value of 6y - 3x is -

Given, x = 30^∘, So, 2x = nbsp;60^∘ Also, 2x + 3y = 180^∘ nbsp; (linear pair) Replacing 2x in the above equation, 60^∘ + 3y = nbsp;180^∘ 3y = nbsp;12 ...

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Standard VI

Mathematics

Adjacent Angles

In the figure...

Question

In the figure below, x = $30^{\circ}$ . The value of (6y – 3x) is ___.

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Solution

Given, x = $30^{\circ}$ ,
So, 2x = $60^{\circ}$

Also, 2x + 3y = $180^{\circ}$ (linear pair)

Replacing 2x in the above equation,
$60^{\circ}$ + 3y = $180^{\circ}$

3y = $120^{\circ}$

y = $40^{\circ}$

The value of 6y - 3x = 240 - 90= $150^{\circ}$

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In the figure below, x = 30∘. The value of (6y – 3x) is ___.

Given, x = 30∘, So, 2x = 60∘ Also, 2x + 3y = 180∘ (linear pair) Replacing 2x in the above equation, 60∘ + 3y = 180∘ 3y = 120∘ y = 40∘ The value of 6y - 3x = 240 - 90= 150∘

In the figure below, x = $30^{\circ}$ . The value of (6y – 3x) is ___.

Given, x = $30^{\circ}$ ,
So, 2x = $60^{\circ}$

Also, 2x + 3y = $180^{\circ}$ (linear pair)

Replacing 2x in the above equation,
$60^{\circ}$ + 3y = $180^{\circ}$

3y = $120^{\circ}$

y = $40^{\circ}$

The value of 6y - 3x = 240 - 90= $150^{\circ}$