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Question

In the figure, block m1 is loaded on block m2. If there is no relative sliding between the blocks and the inclined plane is smooth, the frictional force acting between the blocks is:


A
μm2sinθ
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B
μm1cosθ
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C
μm1sinθ
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D
Zero
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Solution

The correct option is D Zero
Assuming no friction between the surfaces, acceleration of
block 1 is


Since, the blocks can only move along the inclined plane, so all forces to inclined plane will be balanced for respective blocks.

Acceleration of both blocks down the inclined plane is:

a1=Net Forcemass=m1gsinθm1=gsinθ

Acceleration of block 2

a2=Net Forcemass=m2gsinθm2=gsinθ

relative acceleration between blocks 1 and 2 is:
(a1a2)=(gsinθgsinθ)=0

Hence, we can say that there is no tendency of slipping between blocks, as both will move with same acceleration down the incline.
frictional force f=0 between block 1 and block 2.

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