In the figure, calculate:

(a) the total resistance of the circuit,

(b) the value of R, and

(c) the current flowing in R.

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Solution

(a) We know, V = IR

$R equals V over I equals fraction numerator 4 over denominator 0.4 end fraction equals 10 space o h m$

Total resistance, R = 10 ohm

(b) Resistors are in parallel.

(c) We know that,

V = IR

Potential (V) is equal at the two ends.

Let, I₁ be the current flowing through R and I₂ be through 20 ohm.

I₁ + I₂ = 0.4

I₂=(0.4-I₁)

Now, we have V=V

That is,

I₁R₁ = I₂R₂

I₁x 20= (0.4-I₁) x 20

20 I₁ = 8 – 20I₁

40I₁=8

Therefore,

Current flowing through R = 0.2 A

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In the figure, calculate: (a) the total resistance of the circuit, (b) the value of R, and (c) the current flowing in R.

In the figure, calculate:

(a) the total resistance of the circuit,

(b) the value of R, and

(c) the current flowing in R.