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Question

In the figure, current through the 3 Ω resistor is 0.8 ampere, the potential drop through 4 Ω resistor is
1021474_a929f0fed5ce411f900d619f62a5c827.png

A
9.6 V
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B
2.6 V
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C
4.8 V
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D
1.2 V
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Solution

The correct option is C 4.8 V
Let current passing through the circuit is I and through resistor 6Ω is I1 and potential drop through resistor 4Ω is V
Potential drop across resistor 3Ω and 6Ω is same.
Using V=IR, 0.8×3=I1×6 I1=0.4A
I=I1+0.8=1.2A
Potential drop through resistor 4Ω, V=1.2×4=4.8V


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