Question

In the figure, $AB\parallel CD$ and $AD\parallel BC$. Then by SAS congruence postulate, $\Delta ABC\cong$

• A. $\Delta ADC$
• B. $\Delta CDA$
• C. $\Delta ACD$
• D. $\Delta DCA$

Answer 1

Answer: (B)

$\Delta CDA$

In $\Delta ABCand\Delta ADC$
$\angle CAB=\angle DCA$ (Alternate angles)
$AC=AC$
$\angle BCA=\angle DAC$ (Alternate angles)
$\therefore \Delta ABC\cong \Delta CDA$ (By ASA postulate)