Question

In the figure, $AD\parallel BC$ and $AD=BC$. Then $\Delta ABD\cong \Delta CDB$ by congruence postulate.

• A. SSS
• B. ASA
• C. AAS
• D. SAS

Answer 1

The correct option is D SAS

In $\Delta ABD$ and $\Delta CDB$
$AD=BC$
$\angle BDA=\angle DBC$ (Alternate angles)
$BD=BD$
$\therefore \Delta ABD\cong \Delta CDB$ (By SAS postulate)