Question

In the figure, $\angle B={90}^o,\angle D={90}^o$, and $AO=OC$. Then $\Delta BAO\cong \Delta DCO$ by the congruence postulate

• A. SAS
• B. RHS
• C. SSS
• D. AAS

Answer 1

The correct option is D AAS

In $\Delta BAO$ and $\Delta DCO$
$\angle D={90}^o=\angle D$
$\angle AOB=\angle COD$
$AO=OC$
$\therefore \Delta BAO\cong \Delta DCO$ (By AAS congruence postulate)