In the figure, $∠ D A C = ∠ A B D, A B = 20, A D = 10$ and $A C = 12$ . Then DC is equal to

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Solution

The correct option is C 6
Here, $\frac{D C}{A C} = \frac{A D}{A B}$
so, $\frac{D C}{12} = \frac{10}{20}$
$D C = 10 \times \frac{12}{20} = 6$
hence, answer is C

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