In the figure- AO -0 C - BO - OD -1-2 and AB -5 cm- Find the value of CD-Figure 2 -A- 18 cmB- 20 cmC- 10 cmD- 15 cm

The correct option is C 10 cm Δ AOB ∼ Δ COD (SAS similarity) AO/CO=OB/OD=AB/DC Given AO/OC=BO/OD=1/2 ⇒ 2OA = OC and 2OB = OD Since it is a similar triangle AB ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Relation between Sides of Triangle

In the figure...

Question

In the figure, $\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2} a n d A B = 5 c m$ . Find the value of CD .

Figure 2.

10 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

15 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

18 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
10 cm

$Δ A O B \sim Δ C O D (S A S s i m i l a r i t y) \frac{A O}{C O} = \frac{O B}{O D} = \frac{A B}{D C} G i v e n \frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2} \Rightarrow 2 O A = O C a n d 2 O B = O D$

Since it is a similar triangle AB = 2CD = 10cm

Suggest Corrections

Similar questions

In figure, $\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2}$ and AB = 5cm. Find the value of DC.

In the figure, ABCD is a trapezium in which, AB || DC and $\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2} a n d A B = 5 c m$ . Find the value of CD .

Q. In given figure,

\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2}

and AB=5 cm. Find the value of DC.

In the given figure, ABCD is a trapezium in which
(i) AB || CD
(ii) $\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2}$
(iii) AB = 5 cm

Find the value of CD .

Q. Find

x

A O = 8.1 c m, B O = 5 c m, O C = 9 c m

and

O D = x c m .

Join BYJU'S Learning Program

In the figure, AOOC=BOOD=12 and AB=5 cm. Find the value of CD . Figure 2.

The correct option is A 10 cm ΔAOB∼ ΔCOD (SAS similarity)AOCO=OBOD=ABDCGiven AOOC=BOOD=12⇒ 2OA=OC and 2OB=OD Since it is a similar triangle AB = 2CD = 10cm

In the figure, $\frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2} a n d A B = 5 c m$ . Find the value of CD .

Figure 2.

The correct option is A
10 cm

$Δ A O B \sim Δ C O D (S A S s i m i l a r i t y) \frac{A O}{C O} = \frac{O B}{O D} = \frac{A B}{D C} G i v e n \frac{A O}{O C} = \frac{B O}{O D} = \frac{1}{2} \Rightarrow 2 O A = O C a n d 2 O B = O D$

Since it is a similar triangle AB = 2CD = 10cm