In the figure, from one handkerchief from four corners, sectors P, Q, R, S each of 2 cm are cut, whose sum is P + Q + R + S = A1 and a circle of diameter 4 cm from the centre is cut whose area is A2, then .................... is possible
A
A1≠A
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B
A1<A2
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C
A1>A2
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D
A1=A2
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Solution
The correct option is CA1=A2 Handkerchief is in the form of a square. Hence, θ=90o Radius of each minor sector = r = 2cm ∴ Area of four minor sectors =4×πr2θ360 ∴A1=4×22×2×2×907×360=887cm2 For the circle in the middle of the square, diameter d = 4 cm ∴ Radius of the circle =42=2cm ∴ Area of the circle in the middle, A2=227×2×=887cm2 ∴A1=A2