In the figure, from the handkerchief from four corners, sectors P, Q, R and S each of 2cm are cut, whose sum is P+Q+R+S=A1 and a circle of diameter 4cm from the centre is cut whose area is A2, then ______ is possible.
A
A1≠A2
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B
A1<A2
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C
A1>A2
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D
A1=A2
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Solution
The correct option is AA1=A2 In the figure, from one handkerchief from four corners, sectors P, O, R and S of 2cm are cut. ∴A1=P+Q+R+S =4(πr24) ..... (where r=2cm) =π(2)2 =4πcm2........(1) The diameter of the circle lies on centre is 4 cm. ∴ Its radius is 2cm ∴A2=πr2 ...... (where r=2cm) =π(2)2 =4π(cm)2..........(2) From (1) and (2), we have A1=A2