Question

In the figure given, $ABC$ is a right-angled triangle, right-angled at $B$. $BC=21cm$ and$AB=28cm$. With $AC$ as diameter a semicircle and with $BC$ as radius a quarter circle are drawn. What is the area of the shaded portion?

• A. $425{cm}^2$
• B. $425.75{cm}^2$
• C. $428{cm}^2$
• D. $428.75{cm}^2$

Answer 1

The correct option is D $428.75{cm}^2$

Area of shaded region = Area of semicircle + Area of triangle - Area of quarter-circle

$=\frac{\pi \times {\left(\frac{35}{2}\right)}^2}{2}+\frac{28\times 21}{2}-\frac{\pi \times {21}^2}{4}$

$=428.75c{m}^2$