In the figure given above, AP⊥l i.e., AP is the shortest line segment that can be drawn from A to the line l. If PR>PQ, which of the following is true.
A
AQ>AR
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B
AR>AQ
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C
AQ=2AR
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D
AQ=√2AR
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Solution
The correct option is CAR>AQ Cut off PS=PQ from PR join AS In ΔAPQ and ΔAPS ∠APQ=∠APS (each 90∘) AP=AP .... (common side) PQ=PS ∴ΔAPQ≅ΔAPS AP=AS and ∠1=∠3 ....(1) In ΔARS, ∠3>∠2 ....(2) [exterior angle property] from (1) and (2) ∠1>∠2 from ΔAQR, ∠1>∠2 ∴AR>QR ∴AR>AQ