Question

In the figure given below a player is sitting on a top of a tower $20m$ high. It is observed that an angle of depression of a ball lying on the ground is ${60}^o$. Find the distance between the foot of the tower and the ball.

Answer 1

In $\Delta ABC$,
$\tan {60}^o=\frac{AB}{BC}$
$\sqrt{3}=\frac{20}{BC}$
$BC=\frac{20\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}$
$=\frac{20\sqrt{3}}{3}m$