Since D is the mid-point of BC,
From Apollonius theorem,
AB2+AC2=2(BD2+AD2)32+52=2(BD2+42)(9+252)=BD2+16⇒ BD2=17−16⇒ BD=1 cm.
In the figure given below AB = 3 cm, AC = 5 cm and AD = 4 cm and D is the midpoint of BC. Then the length of BD is :