In the figure given below, AB is a straight line. If $∠ A O C = 50 °$ and $∠ B O D = 60 °$ , then find the value of x.

40^{\circ}

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50^{\circ}

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60^{\circ}

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70^{\circ}

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Solution

The correct option is D $70^{\circ}$
$∠ A O C + x + ∠ B O D = 180 °$ [Linear pair of angles]
$50 ° + x + 60 ° = 180 °$
$x + 110 ° = 180 °$
$x = 180 ° - 110 °$
$x = 70 °$

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Similar questions

In the figure below, straight lines AB and CD intersect at O. If $∠$ AOC + $∠$ BOE = $70^{\circ}$ and $∠$ BOD = $40^{\circ}$ , find (2 $∠$ BOE).

In the figure below, lines AB and CD intersect at O. If

$∠ A O C + ∠ B O E = 70^{\circ}$ and

$∠ B O D = 40^{\circ}$ ,

find $(2 ∠ B O E)$ .

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