In the figure given below, AB is a straight line. If $∠ A O C = 50 °$ and $∠ B O D = 60 °$ , then find the value of x.

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Solution

$∠ A O C + x + ∠ B O D = 180 °$ [Linear pair of angles]
$50 ° + x + 60 ° = 180 °$
$x + 110 ° = 180 °$
$x = 180 ° - 110 °$
$x = 70 °$

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Similar questions

Q. In the given figure, AOB is a straight line. If ∠AOC = (3x − 10)°, ∠COD = 50° and ∠BOD = (x + 20)°, then ∠AOC = ?
(a) 40°
(b) 60°
(c) 80°
(d) 50°

In the given figure, AOB is a straight line. If $∠ A O C = (3 x - 10)^{\circ}$ , \angle COD = 50^{\circ}\) and $∠ B O D = (x + 20)^{\circ}$ then $∠ A O C = ?$

(a) $40^{\circ}$

(b) $60^{\circ}$

(d) $50^{\circ}$

Q. Mark (✓) against the correct answer
In the given figure, two straight lines AB and CD intersect at a point O and ∠AOC = 50°. Then, ∠BOD = ?

(a) 40°
(b) 50°
(c) 130°
(d) 60°

Q. In the given figure, two straight lines AB and CD intersect at a point O such that ∠AOC = 50°.
Find: (i) ∠BOD (ii) ∠BOC.

Q. In the adjoining figure, AOB is a straight line. Find the value of x. Hence, find ∠AOC and ∠BOD.

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In the figure given below, AB is a straight line. If ∠AOC=50° and ∠BOD=60°, then find the value of x.

∠AOC+x+∠BOD=180° [Linear pair of angles] 50°+x+60°=180° x+110°=180° x=180°−110° x=70°

In the figure given below, AB is a straight line. If $∠ A O C = 50 °$ and $∠ B O D = 60 °$ , then find the value of x.

$∠ A O C + x + ∠ B O D = 180 °$ [Linear pair of angles]
$50 ° + x + 60 ° = 180 °$
$x + 110 ° = 180 °$
$x = 180 ° - 110 °$
$x = 70 °$