In the figure- given below- AB is perpendicular to CD- AP - CD- - CBP - 138- Find the value of - ABP-

The correct option is D 48^o ∠ CBP = 138^∘ Since, AB is perpendicular CD, #160; ∠ ABC = 90^∘ ∠ CBP = ∠ ABC + ∠ ABP 138^∘ = 90^∘ + ∠ A ...

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Standard IX

Mathematics

Rectangle

In the figure...

Question

In the figure, given below, AB is perpendicular to CD; AP // CD, $∠ C B P = 138^{\circ}$ . Find the value of $∠ A B P$ .

36^{o}

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48^{o}

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26^{o}

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none of the above

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Solution

The correct option is D $48^{o}$
$∠ C B P = 138^{\circ}$

Since, AB is perpendicular CD, $∠ A B C = 90^{\circ}$

$∠ C B P = ∠ A B C + ∠ A B P$
$138^{\circ} = 90^{\circ} + ∠ A B P$
$∠ A B P = 138^{\circ} - 90^{\circ} = 48^{\circ}$

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In the figure, given below, AB is perpendicular to CD; AP // CD, ∠CBP=138∘. Find the value of ∠ABP.

The correct option is D 48o∠CBP=138∘Since, AB is perpendicular CD, ∠ABC=90∘∠CBP=∠ABC+∠ABP138∘=90∘+∠ABP∠ABP=138∘−90∘=48∘

In the figure, given below, AB is perpendicular to CD; AP // CD, $∠ C B P = 138^{\circ}$ . Find the value of $∠ A B P$ .

The correct option is D $48^{o}$
$∠ C B P = 138^{\circ}$

Since, AB is perpendicular CD, $∠ A B C = 90^{\circ}$

$∠ C B P = ∠ A B C + ∠ A B P$
$138^{\circ} = 90^{\circ} + ∠ A B P$
$∠ A B P = 138^{\circ} - 90^{\circ} = 48^{\circ}$