Question

In the figure given below, $AB\parallel CD\parallel EF.$Then the value of x is

• A. ${28}^{\circ }$
• B. ${72}^{\circ }$
• C. ${56}^{\circ }$
• D. ${80}^{\circ }$

Answer 1

The correct option is A ${28}^{\circ }$

$\angle CEF+\angle ECD={180}^o$

(Angles on same side of transversal)

$\angle ECS=180-152-{28}^o$

$\angle ABC=\angle BCD$

(opposite angles)

$\angle ABC=x^o+\angle ECD$

$\Rightarrow {56}^o=x^o+{28}^o$

$\Rightarrow x^o={56}^o-{28}^o$

$\Rightarrow x={28}^o$.