From the question it is given that, AB∥CR and LM∥QR
(i) We have to prove that, BM/MC=AL/LQ
Consider the △ARQ
LM∥QR … [from the question]
So, AM/MR=AL/LQ … [equation (i)]
Now, consider the △AMB and △MCR
∠AMB=∠CMR … [because vertically opposite angles are equal]
∠MBA=∠MCR … [because alternate angles are equal]
Therefore, AM/MR=BM/MC … [equation (ii)]
From equation (i) and equation (ii) we get,
BM/MR=AL/LQ
(ii) Given, BM:MC=1:2
AM/MR=BM/MC
AM/MR=12 … [equation (iii)]
LM∥QR … [given from equation]
AM/MR=LM/QR … [equation (iv)]
AR/AM=QR/LM
(AM+MR)/AM=QR/LM
1+MR/AM=QR/LM
1+(2/1)=QR/LM
3/1=QR/LM
LM/QR=1/3
Therefore, the ratio of LM:QR is 1:3.