Question

In the figure, given below, ABCD is a trapezium. EF is parallel to AD and BC. The measures of the angles marked as x is ${60}^o$

• A. True
• B. False

Answer 1

The correct option is B False

$AD\parallel BC\parallel EF$
Thus, $\angle ACB=x=z$ (Alternate angles of parallel lines are equal)
$x=z={50}^{\circ }$
Also, $\angle EFD+\angle FDA=180$ (Sum of angles on same side of parallel sides is 180)
$120+y=180$
$y={60}^{\circ }$